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Table of Integrals, Series, and Products (비교)

r1 ➤ r2
6[math(\sum_{k=0}^{n-1}(a+kr)=\frac{n}{2}[2a+(n-1)r]=\frac{n}{2}(a+l))] [$[math(l=a+(n-1)r$)]은 마지막 항]
12[math(\sum_{k=0}^{n-1}(a+kr)q^k=\frac{1-q}{a-[a+(n-1)r]q^n}+\frac{(1-q)^2}{rq(1-q^{n-1})})] [$[math(q \neq 1,\ n>1$)]]