r1 ➤ r2 | |
6 | [math(\sum_{k=0}^{n-1}(a+kr)=\frac{n}{2}[2a+(n-1)r]=\frac{n}{2}(a+l))] [$[math(l=a+(n-1)r$)]은 마지막 항] |
12 | [math(\sum_{k=0}^{n-1}(a+kr)q^k=\frac{1-q}{a-[a+(n-1)r]q^n}+\frac{(1-q)^2}{rq(1-q^{n-1})})] [$[math(q \neq 1,\ n>1$)]] |
r1 ➤ r2 | |
6 | [math(\sum_{k=0}^{n-1}(a+kr)=\frac{n}{2}[2a+(n-1)r]=\frac{n}{2}(a+l))] [$[math(l=a+(n-1)r$)]은 마지막 항] |
12 | [math(\sum_{k=0}^{n-1}(a+kr)q^k=\frac{1-q}{a-[a+(n-1)r]q^n}+\frac{(1-q)^2}{rq(1-q^{n-1})})] [$[math(q \neq 1,\ n>1$)]] |